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Proof step 1 from proof restn-firstn (conclusion)
⊦ m ≤ n ∧ m + n ≤ # x → restn(m, firstn(n, x)) = firstn(n - m, restn(m, x))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
m ≤ n, m + n ≤ # x ⊦ restn(m, firstn(n, x)) = firstn(n - m, restn(m, x))
Rule argument
Additional information