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Proof step 2 from proof restn-rest (previous step)

⊦ restn(n, x).rest = restn(n, x.rest)

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ x. restn(n0, x).rest = restn(n0, x.rest) ⊦ restn(n0 +1, x).rest = restn(n0 +1, x.rest)

Rule argument

indvar: n

Additional information

Used simplifier rules: restN-zero: ⊦ restn(0, x) = x;%nat freely generated by 0, +1;;