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Proof step 4 from proof restn-rest (previous step)

∀ x. restn(n0, x).rest = restn(n0, x.rest) ⊦ restn(n0, x.rest).rest = restn(n0, x.rest.rest)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: x.rest

Additional information

Used terms: x.rest