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Proof step 35 from proof rmpos-in (previous step)

m < # x0, a ∈ x0, ∀ n0, a1. n0 < # x0 → (a1 ∈ x0 -1l n0 ↔ a1 ≠ x0[n0] ∧ a1 ∈ x0) ⊦ a = x0[m], x0 = [], a ∈ x0 -1l m, dups(x0), a0 ∈ x0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: m, a

Additional information

Used terms: m, a