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Proof step 1 from proof size-del-nodups (conclusion)

⊦ ¬ dups(x) ∧ a ∈ x → #(x -l a) = # x - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
a ∈ x ⊦ #(x -l a) = # x - 1, dups(x)

Rule argument

Additional information