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Proof step 1 from proof sublist-append-01 (conclusion)

⊦ # x ≤ n → sublist(n, m, x + y) = sublist(n - # x, m, y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# x ≤ n ⊦ firstn(m, restn(n, x + y)) = firstn(m, restn(n - # x, y))

Rule argument

Additional information

Used simplifier rules: sublist-def: ⊦ sublist(m, n, x) = firstn(n, restn(m, x));