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Proof step 1 from proof sublist-append (conclusion)

⊦ n + m ≤ # x → sublist(n, m, x + y) = sublist(n, m, x)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: sublist-def: ⊦ sublist(m, n, x) = firstn(n, restn(m, x));%rest-append: ⊦ n + m ≤ # x → restn(n, x + y) = restn(n, x) + y;%first-append-01: ⊦ n + m ≤ # x → firstn(m, restn(n, x) + y) = firstn(m, restn(n, x));%a: ⊦ (x + y) + z = x + y + z; from specification list%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2