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Proof step 9 from proof sublist-part (previous step)

# x0 = n0 + m, ∀ n0, m0. # x0 = n0 + m0 → firstn(m0, x0) + firstn(n0, restn(m0, x0)) = x0 ⊦ firstn(m, x0) + firstn(n0, restn(m, x0)) = x0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n0, m

Additional information

Used terms: n0, m