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Proof step 1 from proof sublist-restn-02 (conclusion)

⊦ n + m = # x → sublist(n, m, x) = restn(n, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
n + m = # x ⊦ firstn(m, restn(n, x)) = restn(n, x)

Rule argument

Additional information

Used simplifier rules: sublist-def: ⊦ sublist(m, n, x) = firstn(n, restn(m, x));