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Proof step 11 from proof sw-02 (previous step)

(x0 -1l a0) -1l b = (x0 -1l b) -1l a0, ∀ a, b. (x0 -1l a) -1l b = (x0 -1l b) -1l a ⊦ a0 = a, (a0 ' + (x0 -1l a)) -1l b = ((a0 ' + x0) -1l b) -1l a

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 12:
(x0 -1l a0) -1l b = (x0 -1l b) -1l a0, ∀ a, b. (x0 -1l a) -1l b = (x0 -1l b) -1l a ⊦ b = a0, a0 = a, (a0 ' + (x0 -1l a)) -1l b = ((a0 ' + x0) -1l b) -1l a

Rule argument

fma: b = a0

Additional information

Used simplifier rules: del1-y: ⊦ (a ' + x) -1l a = x;%a: ⊦ (x + y) + z = x + y + z; from specification list Used formulas: b = a0