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Proof step 3 from proof sw (previous step)

∀ a, b. (x0 -l a) -l b = (x0 -l b) -l a ⊦ ((a0 ' + x0) -l a) -l b = ((a0 ' + x0) -l b) -l a

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 4:
a = a0, ∀ a, b. (x0 -l a) -l b = (x0 -l b) -l a ⊦ ((a0 ' + x0) -l a) -l b = ((a0 ' + x0) -l b) -l a
Proof step 8:
∀ a, b. (x0 -l a) -l b = (x0 -l b) -l a ⊦ a = a0, ((a0 ' + x0) -l a) -l b = ((a0 ' + x0) -l b) -l a

Rule argument

fma: a = a0

Additional information

Used formulas: a = a0