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Proof step 1 from proof a (conclusion)

⊦ ¬ dups(x + y) → ¬ dups(x) ∧ ¬ dups(y)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: app-05: ⊦ dups(x) → dups(x + y);%app-01-02: ⊦ dups(y) → dups(x + y);%a: ⊦ (x + y) + z = x + y + z; from specification list