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Proof step 1 from proof app-01 (conclusion)

⊦ disj(x, y + z) → disj(x, z)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: app-02: ⊦ disj(x, y + z) ↔ disj(x, y) ∧ disj(x, z);%a: ⊦ (x + y) + z = x + y + z; from specification list