[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 5 from proof d (
previous step
)
dups(x0 + a ' + y), ∀ a, y. (dups(x0 + a ' + y) ↔ dups(x0 + y)) ∨ a ∈ y ∨ a ∈ x0 ⊦ dups(x0 + y), a = a0, a0 ∈ y, a0 ∈ x0, a ∈ y, a ∈ x0
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: a, y
Additional information
Used simplifier rules: a: ⊦ (x + y) + z = x + y + z; from specification list Used terms: a, y