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Proof step 11 from proof dups-lesize (previous step)

# y0 + # z < # x0, a0 ∈ x0, ∀ a0. a0 ∈ x0 → a0 ∈ y0 ∨ a0 ∈ z ⊦ x0 = [], dups(y0 + z), a ∈ z, a ∈ y0, dups(x0), a ∈ x0, a0 ∈ y0, a0 ∈ z

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a0

Additional information

Used terms: a0