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Proof step 1 from proof dups-rmdup-size-equiv (conclusion)

⊦ dups(x) ↔ # x ≠ # rmdup(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# x = # rmdup(x), dups(x) ⊦

Rule argument

Additional information

Used simplifier rules: rm-eq: ⊦ ¬ dups(x) → rmdup(x) = x;