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Proof step 1 from proof dups-switch (conclusion)

⊦ dups(x + y) ↔ dups(y + x)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: dups-sw: ⊦ dups(x + y) → dups(y + x);%a: ⊦ (x + y) + z = x + y + z; from specification list