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Proof step 12 from proof rm-allsize (previous step)

∀ y. (∀ a. a ∈ x0 ↔ a ∈ y) → # rmdup(x0) = # rmdup(y), a = a ∨ a ∈ x0 ↔ a ∈ y, ∀ a0. a0 = a ∨ a0 ∈ x0 ↔ a0 ∈ y ⊦ # rmdup(x0) + 1 = # rmdup(y), a ∈ x0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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