[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 19 from proof rm-allsize (previous step)

a ∈ z, ∀ y. (∀ a. a ∈ x0 ↔ a ∈ y) → # rmdup(x0) = # rmdup(y), ∀ a0. a0 ≠ a → (a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z) ⊦ # rmdup(x0) + 1 = # rmdup(y0 + z), a ∈ y0, a ∈ x0

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 20:
⊦ a ∈ x ↔ (∃ y, z. x = y + (a + z))
Proof step 21:
a ∈ rmdup(z) ↔ (∃ y, z0. rmdup(z) = y + (a + z0)), a ∈ z, ∀ y. (∀ a. a ∈ x0 ↔ a ∈ y) → # rmdup(x0) = # rmdup(y), ∀ a0. a0 ≠ a → (a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z) ⊦ # rmdup(x0) + 1 = # rmdup(y0 + z), a ∈ y0, a ∈ x0

Rule argument

spec: list inst: name: In seq: ⊦ a ∈ x ↔ (∃ y, z. x = y + (a + z)) subst: [a, x] → [a, rmdup(z)] flags:

Additional information

Used terms: a, rmdup(z)