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Proof step 42 from proof rm-allsize (previous step)

∀ y. (∀ a. a ∈ x0 ↔ a ∈ y) → # rmdup(x0) = # rmdup(y), ∀ a0. a0 ≠ a → (a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z) ⊦ # rmdup(x0) = # rmdup(y0 + z), a ∈ x0, a ∈ z, a ∈ y0

User applied rule all left

And obtained the following new goals

Proof step 43:
(∀ a. a ∈ x0 ↔ a ∈ y0 + z) → # rmdup(x0) = # rmdup(y0 + z), ∀ a0. a0 ≠ a → (a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z) ⊦ # rmdup(x0) = # rmdup(y0 + z), a ∈ x0, a ∈ z, a ∈ y0

Rule argument

pos: left 1 terms: y0 + z abort: F discard: T computed: T

Additional information

Used terms: y0 + z