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Proof step 44 from proof rm-allsize (previous step)

∀ a0. a0 ≠ a → (a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z) ⊦ # rmdup(x0) = # rmdup(y0 + z), a0 ∈ x0 ↔ a0 ∈ y0 ∨ a0 ∈ z, a ∈ x0, a ∈ z, a ∈ y0

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a0 abort: F discard: T computed: T

Additional information

Used terms: a0