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Proof step 5 from proof rm-in-02 (previous step)

a0 ∈ x0, ∀ a. a ∈ rmdup(x0) ↔ a ∈ x0 ⊦ a ∈ rmdup(x0) ↔ a ∈ x0

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 6:
a ∈ rmdup(x0), a0 ∈ x0, ∀ a. a ∈ rmdup(x0) ↔ a ∈ x0 ⊦ a ∈ rmdup(x0) ↔ a ∈ x0
Proof step 8:
a0 ∈ x0, ∀ a. a ∈ rmdup(x0) ↔ a ∈ x0 ⊦ a ∈ rmdup(x0), a ∈ rmdup(x0) ↔ a ∈ x0

Rule argument

fma: a ∈ rmdup(x0)

Additional information

Used formulas: a ∈ rmdup(x0)