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Proof step 4 from proof rm-rm-01 (previous step)

a ∈ x0, ∀ y. rmdup(rmdup(x0) + y) = rmdup(x0 + y) ⊦ rmdup(rmdup(a ' + x0) + y) = rmdup((a ' + x0) + y)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
a ∈ x0, ∀ y. rmdup(rmdup(x0) + y) = rmdup(x0 + y) ⊦ rmdup(rmdup(x0) + y) = rmdup(x0 + y)

Rule argument

Additional information

Used simplifier rules: rmdup-y: ⊦ a ∈ x → rmdup(a ' + x) = rmdup(x);%rm-in-05: ⊦ a ∈ x → rmdup(a ' + x + y) = rmdup(x + y);%a: ⊦ (x + y) + z = x + y + z; from specification list