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Proof step 11 from proof rm-size (previous step)

a0 ∈ x0 ∨ a0 ∈ y, ∀ a, y. # rmdup(x0 + a ' + y) = # rmdup(x0 + y) + 1 ∨ a ∈ y ∨ a ∈ x0 ⊦ # rmdup(x0 + a ' + y) = # (a0 ∈ x0 ∨ a0 ∈ y ⊃ rmdup(x0 + y);a0 ' + rmdup(x0 + y)) + 1, a = a0, a ∈ y, a ∈ x0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
a0 ∈ x0 ∨ a0 ∈ y, ∀ a, y. # rmdup(x0 + a ' + y) = # rmdup(x0 + y) + 1 ∨ a ∈ y ∨ a ∈ x0 ⊦ a = a0, # rmdup(x0 + a ' + y) = # rmdup(x0 + y) + 1, a ∈ y, a ∈ x0

Proof step 11 from proof rm-size (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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