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Proof step 3 from proof sym (previous step)

∀ y. disj(x0, y) → disj(y, x0), disj(a + x0, y) ⊦ disj(y, a + x0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
disj(a ' + x0, y), ∀ y. disj(x0, y) → disj(y, x0) ⊦ disj(y, a ' + x0)

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list