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Proof step 13 from proof blastN-len (previous step)

n = m + 1, # y + 1 = n0 + n, ∀ x0, n0, n. # x0 < #(y + a ') → # x0 = n0 + n → # butlastn(n, x0) = n0 ⊦ n = 0, # butlastn(m, y) = n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
# y = n0 + m, ∀ x0, n0, n. # x0 < #(y + a ') → # x0 = n0 + n → # butlastn(n, x0) = n0 ⊦ # butlastn(m, y) = n0

Rule argument

Additional information

Used simplifier rules: oz: ⊦ m + 1 ≠ 0; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2