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Proof step 8 from proof blastN-rec-01 (previous step)

n ≤ # y + 1, ∀ x0, n, a. # x0 < #(y + a0 ') → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ butlastn(n, a ' + y + a0 ') = a ' + butlastn(n, y + a0 ')

User applied rule cut formula

And obtained the following new goals

Proof step 9:
n ≤ # y + 1, ∀ x0, n, a. # x0 < #(y + a0 ') → n ≤ # x0 → butlastn(n, a ' + x0) = a ' + butlastn(n, x0) ⊦ n = 0, butlastn(n, a ' + y + a0 ') = a ' + butlastn(n, y + a0 ')

Rule argument

fma: n = 0

Additional information

Used simplifier rules: butlastN-base: ⊦ butlastn(0, x) = x;%a: ⊦ (x + y) + z = x + y + z; from specification list%app-08: ⊦ a ' + x = a ' + y ↔ x = y; from specification list Used formulas: n = 0