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Proof step 4 from proof butlast-last (previous step)

⊦ x.butlast + x.last = x, x = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ x ≠ [] → x.butlast + x.last = x

Rule argument

spec: list-last inst: name: last-02 seq: ⊦ x ≠ [] → x.butlast + x.last = x subst: [x] → [x] flags: rewrite, current

Additional information

Used terms: x