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Proof step 1 from proof l-02 (conclusion)

⊦ x ≠ [] → (a ' + x).last = x.last

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: lapp: ⊦ y ≠ [] → (x + y).last = y.last;%a: ⊦ (x + y) + z = x + y + z; from specification list