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Proof step 1 from proof lin-02 (conclusion)

⊦ x.last = a ∧ x ≠ [] → a ∈ x

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: lin-01: ⊦ x.last ∈ x ↔ x ≠ [];