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Proof step 10 from proof mk-inj-01 (previous step)

mklist(a, m0) = mklist(a, n - 1), ∀ a, n. mklist(a, m0) = mklist(a, n) → m0 = n ⊦ m0 + 1 = n, n = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
n = m + 1, mklist(a, m0) = mklist(a, m), ∀ a, n. mklist(a, m0) = mklist(a, n) → m0 = n ⊦ m0 + 1 = n, n = 0

Rule argument

spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n, m] flags:

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n, m