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Proof step 27 from proof nodups-butlastn (previous step)

n ≤ # x + 1, n ≤ # x, a ∈ butlastn(n, x), ∀ a, n. a ∈ butlastn(n, x) ∧ n ≤ # x → a ∈ x ⊦ a = a0, a ∈ x

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: a, n

Additional information

Used terms: a, n