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Proof step 2 from proof postfix-is-lessOrEqual (previous step)

∀ x. x ⊒ y0 ↔ x = y0 ∨ x < y0 ⊦ x ⊒ a + y0 ↔ x = a + y0 ∨ x < a + y0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ x. x ⊒ y0 ↔ x = y0 ∨ x < y0 ⊦ x ⊒ a ' + y0 ↔ x = a ' + y0 ∨ x < a ' + y0

Rule argument

Additional information

Used simplifier rules: c: ⊦ a + x = a ' + x; from specification list