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Proof step 1 from proof prefix-app-size-eq (conclusion)

⊦ # x0 = # x1 → (x0 ⊑ x1 + x2 ↔ x0 = x1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# x0 = # x1, x0 ⊑ x1 + x2 ⊦ x0 = x1

Rule argument

Additional information

Used simplifier rules: prefix-app-05: ⊦ x ⊑ x + y;%a: ⊦ (x + y) + z = x + y + z; from specification list