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Proof step 1 from proof rev-disjoint-01 (conclusion)

⊦ disj(rev(x), y) ↔ disj(x, y)

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 2:
∀ x. disj(rev(x), y0) ↔ disj(x, y0) ⊦ disj(rev(x), a + y0) ↔ disj(x, a + y0)

Rule argument

term: y

Additional information

Used simplifier rules: list freely generated by [], +;;%e: ⊦ disj(x, []); from specification list-dup