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Proof step 5 from proof rev-mklist (previous step)

n0 + 1 ≠ 0, ∀ a. rev(mklist(a, n0)) = mklist(a, n0) ⊦ rev(mklist(a, (n0 + 1)-1) + a ') = mklist(a, (n0 + 1)-1) + a '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
∀ a. rev(mklist(a, n0)) = mklist(a, n0) ⊦ rev(mklist(a, n0)) + a ' = a ' + mklist(a, n0)

Rule argument

Additional information

Used simplifier rules: mk-last: ⊦ mklist(a, n) + a ' = a ' + mklist(a, n);%rev-r: ⊦ rev(a ' + x) = rev(x) + a;%oz: ⊦ m + 1 ≠ 0; from specification nat-basic2%Last: ⊦ x + a = x + a '; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%pred: ⊦ (m + 1)-1 = m; from specification nat-basic2