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Proof step 1 from proof rev-rev-identity (conclusion)

⊦ rev(rev(x)) = x

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: x

Additional information

Used simplifier rules: rev-e: ⊦ rev([]) = [];%rev-r: ⊦ rev(a ' + x) = rev(x) + a;%rev-app: ⊦ rev(x + y) = rev(y) + rev(x);%rev-one: ⊦ rev(a ') = a ';%list freely generated by [], +;;%c: ⊦ a + x = a ' + x; from specification list%Last: ⊦ x + a = x + a '; from specification list%a: ⊦ (x + y) + z = x + y + z; from specification list%app-08: ⊦ a ' + x = a ' + y ↔ x = y; from specification list