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Proof step 2 from proof del-02 (previous step)

a ∈ x, a ∈ y, ∀ a0. #oc(a0, x -1l a) ≤ #oc(a0, y -1l a), ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x -1l a) ⊦ #oc(a0, x) ≤ #oc(a0, y) ∧ #oc(a1, y) ≤ #oc(a1, x)

User applied rule case distinction

And obtained the following new goals

Proof step 3:
a ∈ x, a ∈ y, ∀ a0. #oc(a0, x -1l a) ≤ #oc(a0, y -1l a), ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x -1l a) ⊦ #oc(a0, x) ≤ #oc(a0, y)
Proof step 8:
a ∈ x, a ∈ y, ∀ a0. #oc(a0, x -1l a) ≤ #oc(a0, y -1l a), ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x -1l a) ⊦ #oc(a1, y) ≤ #oc(a1, x)

Rule argument

pos: right 1

Proof step 2 from proof del-02 (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information