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Proof step 4 from proof del-02 (previous step)

#oc(a0, y) < #oc(a0, x), a ∈ y, a ∈ x, a0 ∈ x, ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x -1l a), ∀ a0. #oc(a0, x -1l a) ≤ #oc(a0, y -1l a) ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
#oc(a0, y) < #oc(a0, x), a ∈ y, a ∈ x, a0 ∈ x, ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x -1l a), #oc(a0, x -1l a) ≤ #oc(a0, y -1l a) ⊦

Rule argument

pos: left 6 terms: a0 abort: F discard: T computed: F

Additional information

Used terms: a0