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Proof step 24 from proof del-04 (previous step)

perm(y, x), a0 ∈ y, ∀ a. a ∈ x ∨ a ∈ y → #oc(a, x) = #oc(a, y) ⊦ #oc(a0, x) = #oc(a0, y), a0 = a

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a0

Additional information

Used terms: a0