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Proof step 9 from proof del-04 (previous step)

¬ a0 ≠ a, ∀ a. a ∈ x ∨ a ∈ y → #oc(a, x) = #oc(a, y), perm(y, x), a0 ∈ x -1l a ∨ a0 ∈ y -1l a ⊦ #oc(a0, x -1l a) = #oc(a0, y -1l a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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