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Proof step 3 from proof del (previous step)

a ∈ x ⊦ perm(x, a ' + y) ↔ perm(x -1l a, y)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ perm(x, y) ↔ x ⊆m y ∧ y ⊆m x
Proof step 5:
a ∈ x ⊦ x ⊆m a ' + y ∧ a ' + y ⊆m x ↔ perm(x -1l a, y)

Rule argument

spec: inst: name: perm seq: ⊦ perm(x, y) ↔ x ⊆m y ∧ y ⊆m x subst: [y, x] → [a ' + y, x] flags: rewrite, current

Additional information

Used terms: a ' + y, x