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Proof step 8 from proof del (previous step)

a ∈ x ⊦ x ⊆m a ' + y ∧ y ⊆m x -1l a ↔ x -1l a ⊆m y ∧ y ⊆m x -1l a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
a ∈ x, y ⊆m x -1l a ⊦ x ⊆m a ' + y ↔ x -1l a ⊆m y

Rule argument

Additional information