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Proof step 8 from proof delapp (previous step)

∀ a0. #oc(a0, x) + #oc(a0, y) ≤ #oc(a0, y -1l a), ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x) + #oc(a0, y) ⊦ x = []

User applied rule all left

And obtained the following new goals

Proof step 9:
#oc(x.first, x) + #oc(x.first, y) ≤ #oc(x.first, y -1l a), ∀ a0. #oc(a0, x) + #oc(a0, y) ≤ #oc(a0, y -1l a), ∀ a0. #oc(a0, y -1l a) ≤ #oc(a0, x) + #oc(a0, y) ⊦ x = []

Rule argument

pos: left 1 terms: x.first abort: F discard: F computed: F

Additional information

Used terms: x.first