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Proof step 12 from proof nodups (previous step)

#oc(a, y) = 1, #oc(a, x) = 0, ∀ a. a ∈ x ↔ a ∈ y ⊦ dups(y), dups(x)

User applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: a abort: F discard: T computed: T

Additional information

Used simplifier rules: in-05: ⊦ a ∈ x → #oc(a, x) ≠ 0;%notin: ⊦ ¬ a ∈ x → #oc(a, x) = 0; Used terms: a