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Proof step 3 from proof nodups (previous step)

∀ a. a ∈ x ↔ a ∈ y ⊦ x ⊆m y, dups(y), dups(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ a. a ∈ x ↔ a ∈ y ⊦ x ⊆m y, dups(y), dups(x)

Rule argument

Additional information