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Proof step 1 from proof oc-adjoin (conclusion)

⊦ a ≠ b → #oc(a, x ++ b) = #oc(a, x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ #oc(a, x ++ b) = #oc(a, x), a = b

Rule argument

Additional information