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Proof step 1 from proof oc-filt-01 (conclusion)

⊦ ¬ a ∈ y → #oc(a, filter(x, y)) = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: oc-zero: ⊦ #oc(a, x) = 0 ↔ ¬ a ∈ x;%notin-02: ⊦ ¬ a ∈ y → ¬ a ∈ filter(x, y); from specification list-set