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Proof step 5 from proof ocappend (previous step)

∀ a, y. #oc(a, x0 + y) = #oc(a, x0) + #oc(a, y) ⊦ #oc(a, x0 + y) = #oc(a, x0) + #oc(a, y)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: a, y

Additional information

Used terms: a, y