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Proof step 1 from proof ocs-del-del1 (conclusion)

⊦ #oc(a, x) = 1 → x -l a = x -1l a

User applied rule structural induction

And obtained the following new goals

Proof step 2:
∀ a. #oc(a, x0) = 1 → x0 -l a = x0 -1l a ⊦ #oc(a, a0 + x0) = 1 → (a0 + x0) -l a = (a0 + x0) -1l a

Rule argument

indvar: x

Additional information

Used simplifier rules: oc-e: ⊦ #oc(a, []) = 0;%list freely generated by [], +;;